Find Tutor

Geometric sequences and finite sums

A geometric sequence has a constant ratio r between consecutive terms. Its nth term is uₙ = u₁rⁿ⁻¹. For r ≠ 1, Sₙ = u₁(1 − rⁿ)/(1 − r).

The idea

Find the common ratio by dividing a term by the preceding non-zero term. Ratios greater than one create growth for positive starting values. A negative ratio makes signs alternate. When r = 1, all terms are equal and the finite sum is simply nu₁. Keep the ratio exact until the final calculation to reduce rounding errors.

Worked example

For 3, 6, 12, 24, … find the fifth term and the sum of the first five terms.

  1. u₁ = 3 and r = 2.
  2. u₅ = 3 × 2⁴ = 48.
  3. S₅ = 3(1 − 2⁵)/(1 − 2) = 93.

A mistake to avoid

A constant difference indicates an arithmetic sequence; a constant ratio indicates a geometric sequence. Check the pattern before choosing a formula.

Check your understanding

What is the fourth term of 16, 8, 4, …?

Show the explanation

The ratio is ½. The fourth term is 16 × (½)³ = 2.

Explore the lesson

This guide connects to Geometric sequences and series in the IB Mathematics: Analysis and Approaches course. The first two published lessons per subject are free previews; further interactive lessons require an account.

Keep learning